x^2=4(x-3)

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Solution for x^2=4(x-3) equation: 



x^2=4(x-3)

We move all terms to the left:

x^2-(4(x-3))=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

x^2-4x+12=0

a = 1; b = -4; c = +12;
Δ = b2-4ac
Δ = -42-4·1·12
Δ = -32
Delta is less than zero, so there is no solution for the equation

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